Converts A && A.B into A?.B (#54342)

Implements the ?. operator, replacing code like A && A.B with A?.B

BYOND Ref:
When reading A?.B, it's equivalent to A && A.B except that A is only evaluated once, even if it's a complex expression like a proc call.
This commit is contained in:
ZeWaka
2020-10-13 16:43:53 -03:00
committed by GitHub
parent a92fcb5295
commit 9629feed35
214 changed files with 377 additions and 377 deletions
@@ -8,7 +8,7 @@
if(!check_rights(R_VAREDIT))
return
if(A && A.type)
if(A?.type)
method = vv_subtype_prompt(A.type)
src.massmodify_variables(A, var_name, method)
@@ -114,7 +114,7 @@
var/list/varsvars = vv_parse_text(O, new_value)
var/pre_processing = new_value
var/unique
if (varsvars && varsvars.len)
if (varsvars?.len)
unique = alert(usr, "Process vars unique to each instance, or same for all?", "Variable Association", "Unique", "Same")
if(unique == "Unique")
unique = TRUE
@@ -23,7 +23,7 @@ GLOBAL_PROTECT(VVpixelmovement)
var/list/subtypes = subtypesof(type)
if (!subtypes || !subtypes.len)
return FALSE
if (subtypes && subtypes.len)
if (subtypes?.len)
switch(alert("Strict object type detection?", "Type detection", "Strictly this type","This type and subtypes", "Cancel"))
if("Strictly this type")
return FALSE