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Converts A && A.B into A?.B (#54342)

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Implements the ?. operator, replacing code like A && A.B with A?.B

BYOND Ref:
When reading A?.B, it's equivalent to A && A.B except that A is only evaluated once, even if it's a complex expression like a proc call.
This commit is contained in:
ZeWaka
2020-10-13 16:43:53 -03:00
committed by GitHub
parent a92fcb5295
commit 9629feed35
214 changed files with 377 additions and 377 deletions
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code/modules/modular_computers/computers/item/computer_power.dm
+2 -2
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@@ -5,7 +5,7 @@
var/obj/item/computer_hardware/recharger/recharger = all_components[MC_CHARGE]
if(recharger && recharger.check_functionality())
if(recharger?.check_functionality())
if(recharger.use_power(amount))
return TRUE
@@ -22,7 +22,7 @@
/obj/item/modular_computer/proc/give_power(amount)
var/obj/item/computer_hardware/battery/battery_module = all_components[MC_CELL]
if(battery_module && battery_module.battery)
if(battery_module?.battery)
return battery_module.battery.give(amount)
return 0