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Converts A && A.B into A?.B (#54342)

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Implements the ?. operator, replacing code like A && A.B with A?.B

BYOND Ref:
When reading A?.B, it's equivalent to A && A.B except that A is only evaluated once, even if it's a complex expression like a proc call.
This commit is contained in:
ZeWaka
2020-10-13 16:43:53 -03:00
committed by GitHub
parent a92fcb5295
commit 9629feed35
214 changed files with 377 additions and 377 deletions
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code/modules/modular_computers/file_system/programs/cargoship.dm
+1 -1
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@@ -20,7 +20,7 @@
data["has_id_slot"] = !!card_slot
data["has_printer"] = !!printer
data["paperamt"] = printer ? "[printer.stored_paper] / [printer.max_paper]" : null
data["card_owner"] = card_slot && card_slot.stored_card ? id_card.registered_name : "No Card Inserted."
data["card_owner"] = card_slot?.stored_card ? id_card.registered_name : "No Card Inserted."
data["current_user"] = payments_acc ? payments_acc.account_holder : null
data["barcode_split"] = percent_cut
return data