ZeWaka 9629feed35 Converts A && A.B into A?.B (#54342) ...

Implements the ?. operator, replacing code like A && A.B with A?.B

BYOND Ref:
When reading A?.B, it's equivalent to A && A.B except that A is only evaluated once, even if it's a complex expression like a proc call.

2020-10-13 16:43:53 -03:00

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